Question

if (x+1) and (x-1) are the factors of p(x)=ax cube +x square -2x +b find the values of a and b The polynomials and when divided by leave the remainders and respectively. If , find the value of 'a'.

Answer 1

Answer:

a=2 b=0 hopefully this helps

Answer 2

Step-by-step explanation:

put x+1=0

x= -1

now,

p(-1)=a(-1)³+(-1)²-2×(-1)+b

= -a+1+2+b

= -a+3+b

according to question,

p(-1)=0

-a+3+b=0

-a+b=-3

put x-1=0

x=1

now,

p(1)=a(1)³+(1)²-2×1+b

= a+1-2+b

= a-1+b

according to question,

p(1)=0

-a-1+b=0

a+b=1

value of a= remainder of 1 - remainder of 2

= -a+b= -3

a+b= 1

_________

-2a. = -4

a= -4/-2

a=2

put in equation 2

a+b=1

2+b=1

2-1=b

1=b