if (x+1) and (x-1) are the factors of px³+x² -2x + q then find the value of p and q
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Answer:
p = 2
q = -1
Step-by-step explanation:
Let p(x) = px³ + x² - 2x + q
Since (x+1) and (x-1) are factors, (-1) and 1 are zeros according to factor theorem.
p(-1) = p(-1)³ + (-1)² - 2(-1) + q = -p + 1 + 2 + q = -p + 3 + q = 0
p(1) = p(1)³ + (1)² - 2(1) + q = p + 1 - 2 + q = p - 1 + q = 0
-p + 3 + q = p - 1 + q
3 + 1 = p + p + q - q
4 = 2p
∴p = 4/2 = 2
p(-1) = -p + 3 + q = 0
-2 + 3 + q = 0
1 + q = 0
∴q = -1
(OR)
p(1) = p - 1 + q = 0
2 - 1 + q = 0
1 + q = 0
∴q = -1
∴ Values of p and q are 2 and -1 respectively.
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