if x-1 and x+2 are factors of polynomial 2x^3+mx^2-x-n then value of m^2+n^2 is
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Answer: 61
Step-by-step explanation:
Since (x−1) is a factor of given polynomial.
∴x=1 will satisfy the given equation.
Let, f(x)=2x3+mx2−x−n
Then f(1)=0
⇒2+m−1−n=0
or, m−n=−1..........(1)
Also (x+2) is a factor of f(x).
∴x=−2 will satisfy the given equation.
Then f(−2)=0
⇒−16+4m+2−n=0
⇒4m−n=14........(2)
From (1) and (2) we get, m=5 and n=6.
Now, m2+n2
=5^2+6^2
=25+36
=61.
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