If x-1 and x-2 are factors of polynomial x^3-px^2+qx-6,then find the value of p and q
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Step-by-step explanation: x³ - px² + qx - 6
x-1
x = 1
1³ - p(1)² + q(1) - 6 = 0
1 -p +q -6 = 0
-p +q -6 +1 = 0
-p + q -5 = 0
p - q = -5 ---------- (i)
x-2
x=2
2³ - p(2)² + q(2) - 6 = 0
8 - 4p + 2q - 6 = 0
-4p +2q - 6 + 8 = 0
-4p + 2q + 2 = 0
4p -2q = 2 ---------- (ii)
p - q = -5 x4
4p -2q = 2 x1
4p -4q = -20 ----------- (iii)
4p - 2q =2 ------------ (iv)
Subtract equ iv from equ iii
-2q = -22
q = 11
p - q = -5
p - 11 = -5
p = -5 + 11
p = 6
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