If (x+1) and ( x+2) are factors of xcube + 3x square - 3ax + b the find a and b
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Answered by
1
here u go....hope this helps
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Answered by
2
Hey !!!
.
.
If x+1 and x+2 are factors than, we can say that,
x=-1 and x=-2
Now, By putting x=-1 in equation,
(-1)^3 + 3(-1)^2 - 3a(-1) + b
= -1 + 3 + 3a + b
= 2+3a +b
Now by Putting x=-2 in equation,
(-2)^3 + 3(-2)^2 - 3a(-2) + b
=> -8 + 12 +6a + b
= 4 + 6a + b
.
.
Now,
2+ 3a + b =4 + 6a + b
= 3a-6a+b-b = 4 - 2
= -3a = 2
= a = -2/3
and b = 0
.
.
I Hope it May help You
Plzz mark as brainliest......
.
.
If x+1 and x+2 are factors than, we can say that,
x=-1 and x=-2
Now, By putting x=-1 in equation,
(-1)^3 + 3(-1)^2 - 3a(-1) + b
= -1 + 3 + 3a + b
= 2+3a +b
Now by Putting x=-2 in equation,
(-2)^3 + 3(-2)^2 - 3a(-2) + b
=> -8 + 12 +6a + b
= 4 + 6a + b
.
.
Now,
2+ 3a + b =4 + 6a + b
= 3a-6a+b-b = 4 - 2
= -3a = 2
= a = -2/3
and b = 0
.
.
I Hope it May help You
Plzz mark as brainliest......
sanju7238:
thank-you very much
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