If (x-1) and (x+2) are the factors of f(x)=3x² + ax-bx + 2c, then find the value of a + 2b-c.
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Answer:
Since, x+1 is a factor of p(x)=2x
3
+ax
2
+2bx+1
Then, by factor theorem, p(−1)=0
⇒−2+a−2b+1=0⇒a−2b=1 ...(i)
Also,2a−3b=4 ...(ii)
On multiplying (i) by 2 and (ii) by 1, we get
2a−4b=2
−
2
a
+
−
3b=
−
4
−b=−2
∴b=2
On putting b=2 in (i), we get
a−2×2=1⇒a=5
∴a=5,b=2
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