If (x-1) and (x+2) are the factors of f(x) = 3x³ + ax-bx + 2c, then find the value of a + 2b-c.
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the answer is 15
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the value of a+2b-c is 15 if (x-1) an (x+2) are the factors of f(x)=3x³ + ax² - bx + 2c
Given:
- (x-1) an (x+2) are the factors of f(x)
- f(x) = 3x³ + ax² - bx + 2c
To Find:
- Value of a + 2b - c
Solution:
- Factor Theorem. x – a is a factor of the polynomial p(x), if p(a) = 0.
- Also, if x – a is a factor of p(x), then p(a) = 0,
- where a is any real number.
Step 1:
x - 1 is a factor of f(x) hence f(1) = 0
3(1)³ + a(1)² - b(1) + 2c = 0
=> 3 + a - b + 2c = 0
=> a - b + 2c = - 3 Eq1
Step 2:
x + 2 is a factor of f(x) hence f(-2) = 0
3(-2)³ + a(-2)² - b(-2) + 2c = 0
=> -24 + 4a +2b + 2c = 0
=> 4a +2b + 2c = 24
=> 2a + b + c = 12 Eq2
Step 3:
Eq2 - Eq1
=> a + 2b - c = 15
Hence, the value of a+2b-c is 15
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