If (x + 1) and (x + 2) are the factors of the
polynomial xº + 13x2 + ax + b, find the
values of a and b.
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Let p(x) = x³+13x²+ax+b
Since (x+1) and (x+2) are factors of p(x),
-1 and -2 are the zeroes of the equation
Hence,
p(-1) = 0
p(-2) = 0
p(-1) = (-1)³ + 13(-1)² - a + b = 0
-1+13-a+b = 0
a-b = 12 ------(1)
p(-2) = (-2)³ + 13(-2)² -2a + b =0
b-2a = 8-52
b-2a = -48 -------(2)
(1)+(2) => a-b+b-2a = 12-48
-a = -36
a = 36
a-b = 12
b = a-12
b = 36-12
b = 24
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