Question

if (x+1) and (x+2) are the factors of x3+3x2-3ax+b, then find the value of a and b
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Answer 1

$(x + 1)and(x + 2) \\ {x}^{3} + {3x}^{2} - 3ax + b \\ x = - 1put \: krne \: per \\ - 1 + 3 + 3a + b \\ 3a + b = - 2....(i) \\ x = - 2put \: karne \: per \\ { - 2}^{3} + 3 \times { - 2}^{2} - 3a \times - 2 + b \\ - 8 + 12 + 6a + b \\ 6a + b = - 4......(ii) \\ 3a + b = - 2 \\ 6a + b = - 2 \\ subtraction \: karne \: per... \\ - 3a = 0 \\ a = 0 \\ b = - 2 - 3a \\ b = - 2 - 3 \times 0 \\ b = - 2 \\ hope \: its \: help \: u...$

Answer 2

(x+1) and (x+2) are factors
.: x = -1 or x = -2. -8+12+6a+b

PUT x = -1

.: -1+3+3a+b
.: 2+3a+ b
.: 3a + b = -2 -----------(1)

PUT x = -2

.: -8+12+6a+b
.: 4+6a+b
.: 6a + b = -4 --------------(2)

SUBTRACT (1) FROM (2)

.: 3a = -2
.: a = -2÷3

PUT a = -2÷3 IN (1)

3a + b = -2
.: 3(-2÷3) + b = -2
.: -2 + b =-2
.: b = 0

.: a = -2÷3 and b = 0 is the value of a and b...
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