Question

if x=1 and x=2 are the zeros of the polynomial then p(x)=x3+10x2+ax+b then find the values of a and b

Answer 1

substitude x = 1

1 + 10 + a + b = 0

a + b = -11

x = 2

8 + 40 + 2a + b = 0

2a + b = -48

a = -37

b = 26

Answer 2

Answer:

given that p (x)=x^3+10x^2+ax+b.

p (1)=1+10+a+b.

= 11+a+b.

-11=a+b.

again, p (2)=8+40+2a+b.

=48+2a+b.

-48=2a+b.

now 2a+b=-48.

a+b=-11. now subtract it.

a= -37. & b=26.

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