Math, asked by jyothipappu1976, 9 months ago

if x-1 and x+3 are factors of x³-ax²-13+b find the value of a and b​

Answers

Answered by manimodala73
1

Step-by-step explanation:

x = 1, x = -3. be the solutions

1 - a - 13 + b = -27 -9a -13 +b

28 = -8a

a = -7/2

then substitute a in eq and get b

1 +7/2 -13 + b =0

b = 17/2

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Answered by EuphoricEpitome
0

Answer:

x-1= 0,x=1

p(x)= x^3-ax^2-13+b

p(1)= 1-a-13+b

-a-12+b= 0

b-a= 12....(1)

x+3=0,x= -3

p(-3)= (-3)^3-a(-3)^2-13+b

= -27-9a-13+b

-40-9a+b= 0

-9a+b= 40...(2)

b= 40+9a.

by substituting the value in equation 1.

(40+9a)-a= 12

40+9a-a= 12

8a= -28

a= -28/8= -7/2= -3.5

by substituting the value of a ..in equation 1

b-a= 12

b-(-3.5)= 12

b+3.5= 12

b= 12-3.5

b= 8.5

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