if x-1 and x+3 are factors of x³-ax²-13+b find the value of a and b
Answers
Answered by
1
Step-by-step explanation:
x = 1, x = -3. be the solutions
1 - a - 13 + b = -27 -9a -13 +b
28 = -8a
a = -7/2
then substitute a in eq and get b
1 +7/2 -13 + b =0
b = 17/2
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Answered by
0
Answer:
x-1= 0,x=1
p(x)= x^3-ax^2-13+b
p(1)= 1-a-13+b
-a-12+b= 0
b-a= 12....(1)
x+3=0,x= -3
p(-3)= (-3)^3-a(-3)^2-13+b
= -27-9a-13+b
-40-9a+b= 0
-9a+b= 40...(2)
b= 40+9a.
by substituting the value in equation 1.
(40+9a)-a= 12
40+9a-a= 12
8a= -28
a= -28/8= -7/2= -3.5
by substituting the value of a ..in equation 1
b-a= 12
b-(-3.5)= 12
b+3.5= 12
b= 12-3.5
b= 8.5
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