If x + 1 and x minus 1 hour factor of m x cube + x square - 2 x + 10 find the value of m and n
Answers
Answer:
Step-by-step explanation:
(x + 1) & (x - 1) are factor of
mx³ + x² - 2x + 10
Putting x = 1
m + 1 - 2 + 10 = 0
=> m = 9
Putting x = -1
-m + 1 + 2 + 10 = 0
=> m = 13
So Data is wrong also n is not there in equation
now let say n is there instead of 10
mx³ + x² - 2x + n
then
m + 1 - 2 + n = 0
=> m + n = 1
-m + 1 + 2 + n = 0
=> -m + n= -3
Adding both
2n = -2
=> n = -1
m -1 = 1
=> m = 2
2x³ + x² - 2x - 1 = (x + 1)(x-1)(2x + 1)
Answer:
m = 2, n = -1
Step-by-step explanation:
Given If x + 1 and x minus 1 hour factor of m x cube + x square - 2 x + n find the value of m and n
Given equation will be m x^3 + x^2 – 2 x + n
(x – 1) and (x + 1) are factors of the given polynomial.
x – 1 = 0
x = 1
x + 1 = 0
x = - 1
Put x = 1 in
m x^3 + x^2 – 2 x + n
m(1)^3 + (1)^2 – 2(1) + n = 0
m + 1 – 2 + n = 0
m – 1 + n = 0
m + n = 1-------------1
Now put x = - 1
m(-1)^3 + (-1)^2 – 2(-1) + n = 0
-m + 1 + 2 + n = 0
-m + 3 + n = 0
-m + n = -3-----------------2
Adding 1 and 2 we get
m + n = 1
-m + n = -3
--------------------------------
2n = -2
n = - 1
m + n = 1
m + (-1) = 1
m = 1 + 1
m = 2
Therefore m = 2 and n = -1