Question

If x = 1 and y = 1 then prove that (x+y)^2 =x^2+ 2xy +y^

Answer 1

Answer:

Given ': x=1 , y =1

LHS: (x+y) (x+y)

= (1 +1) (1+1) (putting value of x and y)

=2 x 2

= 4

RHS: x^2 + 2xy + y^2

= 1 + 2 + 1 (putting value of x and y)

= 4

There fore, LHS= RHS

Hence, Proved.

Answer 2

Question:prove that (x+y)²=x²+y²+2xy

Step-by-step explanation:

(x+y)²=(x+y)(x+y)

x(x+y)+y(x+y)

x²+xy+yx+y²

x²+2xy+y²

Hence proved.

Please mark as brainliest.