Question

if x=1 and y=2 is the solution of the simultaneous equation ax+by=2 and bx+a2y=10, find the value of a and b

Answer 1

Answer:

Step-by-step explanation:

• Substitute x=1, y=-2 in the given simultaneous equations, then

• (1) a-b= -2

• (2) a-2b = -6

• Subtract the second equation from the first

• b = 4

• a = 2

• substitute a=2, b=4 in the given simultaneous equations, then

• (3) 2x -y = 4, then y = 2x -4

• (4) 2x^2 +4xy = 3y

• substitute y = 2x -4 in equation 4

• The resulting equation is

• 5x^2 -11x +6 = 0

• factor the equation

• (5x -6) * (x -1) = 0

• x = 6/5 and x = 1

• Using equation 3, substitute for x

• if x = 6/5, y = 2(6/5) -4 = -8/5

• if x = 1, y = 2(1) -4 = -2

• x=1, y=-2 and x=6/5, y=-8/5

Answer 2

Step-by-step explanation:

putting ×=1 y =2

ax+by=2

or,,a+2b=2

or, a=2-2b

bx+2ay=10

or, b+4a=10

or, b+4(2-2b)=10

or, b+8-8b=10

or, -7b=2

or, b= -2/7