Question

if x=1 and y=2, the value of x^2+5xy+y^2/x^2-y^2 is- (a)-5 (b)5 (c)3 (d)0​

Answer 1

⟅A⟆⟅n⟆⟅s⟆⟅w⟆⟅e⟆⟅r⟆✪

Refer to the Attachment✪

option a is correct ✅✪

Answer 2

$\bf\huge\fcolorbox{red}{yellow}{Answer = -5}$

$\bf\huge{\underline{\underline{Explaination :-}}}$

$\bf\dfrac{x^2 + 5xy + y^2}{x^2 - y^2}$

Given:

• x = 1
• y = 2

Putting the value of x and y

$\dfrac{(1)^2 + 5(1)(2) + (2)^2}{(1)^2 - (2)^2}$

=> $\dfrac{1 + 10 + 4}{1 - 4}$

=> $\dfrac{15}{-3}$ = -5