Question

if x=1 and y=6 ,find value of k in linear equation 8x-ky+k^2=0

Answer 1

Step-by-step explanation:

k^2-ky+8x=0

Substituting the value of x=1 & y=6

Therefore, k^2-k(6)+8(1)=0

k^2 - 6k +8=0

k^2 - 4k-2k+8=0

k( k- 4) -2(k- 4)=0

(k- 2) (k - 4)=0

Hence, k= 2 &4

Hope you got your answer

Thank you

mark me as brainliest