Question

If x= 1 and y=6 is a solution of the equation 8x-ay+a^2=0 , find the values of a .....

Answer 1

Step-by-step explanation:

8×1 - a×6 + a×a = 0

= 8 - 6a + a^2 = 0

= 8 - a ( 6 + a ) = 0

If 8-a is 0, then a = 8

and

If 6+a is 0, then a = -6

Ans : a = 8 or -6

Hope this would satisfy your question

pls mark me the brainliest