Math, asked by kemagedai6226, 11 months ago

If x=1 and y=6 is a solution of the equation 8x-ay+a²=0, find the values of a.

Answers

Answered by nikitasingh79
1

Given : x = 1 and y = 6 is a solution of the equation 8x - ay + a² = 0.

 

To find : values of a

Solution :  

We have 8x - ay + a² = 0 ………(1)

On Substituting x = 1 and y = 6 in eq 1, we obtain,

⇒ 8 × (1) – a × (6) +  a² = 0

⇒ 8 - 6a + a² = 0

⇒ a² - 6a + 8 = 0

⇒ a² - 4a - 2a + 8 = 0

[By middle term splitting]

⇒ a(a - 4) - 2(a - 4) = 0

⇒ (a - 2)(a - 4) = 0

⇒ a = 2, 4

Hence the values of 'a' are 2 & 4.

HOPE THIS ANSWER WILL HELP YOU…..

 

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Answered by Anonymous
0

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