Question

If x=1 and y = 6 is a solution of the equation 8x-ay+a²=0, find the value of a?​

Answer 1

Answer:

x=1  y=6

• 8x-ay+a^=0
• 8(1)-a(6)+a^=0
• 8-a6+a^=0
• -a6+a^=0-8
• -a+a^=-8/6
• a=$\sqrt{-8/6}$

a=$\sqrt{-4/3}$

Step-by-step explanation:

Answer 2

Answer:

(8×1)-6a+a^2=0

a^2-6a+8=0

a(a-2)-4(a-2)=0

(a-2)(a-4)=0

a=2,4

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