Question

If x=1 and y=6 is a solution of the equation bx-ay+a^2=0 find the value of



a.

Answer 1

$b \times 1 - a6 + a \times 2 \\ b - 6a +2a \\ b - 4a = 0 \\ b = 4a \\ bx - ay + 2a \\ 4a - 6a + 2a \\ - 2a + 2a \\ 0$