if X=1 and y=6 is a solution of the linear equation 8x-ky+k^2=0 , find the value of the k
Answers
Answered by
1
Step-by-step explanation:
just put this values in this equation u get urs answer perfectly
Answered by
2
Answer:
k has two values k= 2
k= 4
Step-by-step explanation:
8(1)-k(6)+k^2= 0
8-6k+k^2= 0
k^2-6k+8
k^2-4k-2k+8
k(k-2)-4(k-2)
(k-2)(k-4)
k= 2, k= 4
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