Question

if x=1 and y=6 is a solution of the linear equation . 8x-ky+k^2=0 Find the value of k

Answer 1

HLO MATE ✋✋
Simran Here !!!!

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Given That : x= 1 & y = 6 .....
So, Putting the values of x & y in linear equation....

8x - ky + k^2 = 0
8(1) - k (6) + k^2 = 0
8 - 6k + k^2 = 0
k^2 - 6k + 8 = 0
k^2 - 4k - 2k + 8 = 0
k(k-4) - 2(k-4) = 0
(k- 4) (k-2) = 0

So , k = 4 & k = 2✔✔
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HOPE IT HELPS UH ✌✌
^_^

Answer 2

Hey there!

The given values x = 1 and y = 6

equation :- 8x - ky + k² = 0

If we substitute, we get,

( 8 ) ( 1 ) - ( k ) ( 6 ) + k² = 0

8 - 6k + k² = 0

k² - 6k + 8 = 0

If we take the factors of the number 8 and elaborate it, we get

k² - 2k - 4k + 8 = 0

k ( k - 2 ) - 4 ( k - 2 ) = 0

( k - 4 ) ( k - 2 ) = 0

Now, k has 2 values,

k - 4 = 0 AND k - 2 = 0

k = 4 AND k = 2

K = 4 , 2

Hope my answer helps!