if x=1 and y=6 the solution of the equation 8x-ay+a²=0
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Step-by-step explanation:
x=1 ,y=6
a^2-ay+8x=0
a^2-6a+8=0
a^2-4a-2a+8=0
a(a-4)-2(a-4)=0
(a-2)(a-4)=0
a=2. or a=4
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