If x= 1 and y = 7 is a solution of the equation a²x - ay + 12, find the values of a.
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x=1,and y=7
so,
a^2x-ay+12=0
a^2×1-a×7+12=0
a^2-7a+12=0
a^2-3a-4a+12=0
a(a-3)-4(a-3) =0
(a-4)(a-3) =0
a-4=0
a=4
a-3=0
a=3
a=4, 3
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