Question

if x = - 1 by 3 is zero polynomial P X equal to 27 x cube minus ax square minus x + 3 then find the value of a

Answer 1

Answer:

The value of a is 21    

Step-by-step explanation:

$\text{Given }x=-\frac{1}{3}\text{ is zero of the polynomial P(x) which is }P(x)=27x^3-ax^2-x+3$

we have to find the value of a

$P(x)=27x^3-ax^2-x+3$

$\text{As }\frac{-1}{3}\text{ is zero of the polynomial therefore by remainder theorem}$

$P(-\frac{1}{3})=0$

$27(-\frac{1}{3})^3-a(-\frac{1}{3})^2-(-\frac{1}{3})+3=0$

$27(-\frac{1}{27})-a(\frac{1}{9})+\frac{1}{3}+3=0$

$-1-\frac{a}{9}+\frac{10}{3}=0$

$\frac{a}{9}=\frac{7}{3}$

$a=\frac{7}{3}\times 9=21$

Hence, the value of a is 21

Answer 2

Answer:21

Step-by-step explanation:see the image below