If x + 1 by x =40 and xy=6,find the value of 2x+y
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Step-by-step explanation:
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We know that,
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( a + b )² = a² + 2ab + b²
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According to the problem given,
4x² + y² = 40-------( 1 )
xy = 6----------------( 2 )
Do the square of ( 2x + y ),
( 2x + y )² = ( 2x )² + 2 × 2x×y + y²
= 4x² + 4xy + y²
= 4x² + y² + 4xy
= 40 + 4 × 6
[ from ( 1 ) and ( 2 ) ]
( 2x + y )² = 40 + 24
= 64
Therefore ,
2x + y = ±√64
= ± 8
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