if X + 1 by x is equal to 3 then find the value of x cube + 1 by x cube
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Given
x + 1/x = 3
Cubing both the sides,
(x + 1/x)³ = (3)³
Now using the identity
(a + b)³ = a³ + b³ + 3ab(a + b)
=> (x + 1/x)³ = (3)³
=> x³ + 1/x³ + 3x × 1/x(x + 1/x) = 27
=> x³ + 1/x³ + 3(x + 1/x) = 27
=> x³ + 1/x³ + 3(3) = 27
(since x + 1/x = 3 given)
=> x³ + 1/x³ + 9 = 27
=> x³ + 1/x³ = 27 - 9
=> x³ + 1/x³ = 18
18 is your answer
Hope it helps dear friend ☺️
x + 1/x = 3
Cubing both the sides,
(x + 1/x)³ = (3)³
Now using the identity
(a + b)³ = a³ + b³ + 3ab(a + b)
=> (x + 1/x)³ = (3)³
=> x³ + 1/x³ + 3x × 1/x(x + 1/x) = 27
=> x³ + 1/x³ + 3(x + 1/x) = 27
=> x³ + 1/x³ + 3(3) = 27
(since x + 1/x = 3 given)
=> x³ + 1/x³ + 9 = 27
=> x³ + 1/x³ = 27 - 9
=> x³ + 1/x³ = 18
18 is your answer
Hope it helps dear friend ☺️
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