Question

If (x+1)cot²30°=2cos²60°+3÷4sec²45°+4sin²30° find the value of "x"​

Answer 1

Refer The Attachment ⬆️

Value of x is

• $\frac{ - 41}{48}$

@MrMonarque

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Answer 2

Solution :

Given that :

(x+1)cot²30° = (2cos²60° + 3) ÷ (4sec²45°+4sin²30°)

As we know that :

sin30° = 1/2,

cos60° = 1/2,

sec45° = √2

And cot30° = √3

Now, on putting the values in the given statement :

(x+1)(√3)² = [ 2(1/2)² + 3 ] ÷ [ 4(√2)² + 4(1/2)² ]

=> 3(x+1) = ( 2 × 1/4 + 3 ) ÷ ( 4 × 2 + 4 × 1/4 )

=> 3x + 3 = ( 1/2 + 3 ) ÷ ( 8 + 1 )

=> 3x + 3 = 7/2 ÷ 9

=> 3x + 3 = 7/2 × 1/9

=> 3x + 3 = 7/18

=> 3x = 7/18 - 3

=> 3x = (7 - 54)/18

=> 3x = -47/18

=> x = -47/18×3

=> x = -47/54

So, the value of x will be -47/54 ✔✔

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