Math, asked by varshi1817, 7 months ago

if (x-1) cube = 8 ,what is the value of (x+1) square​

Answers

Answered by diwakar293165
0

Answer:

16

Step-by-step explanation:

(x-1) ^3=8

(x-1) =8^1/3

x-1=2

x=3

(x+1)^2=(3+1)^2=16

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