Question

If (x-1) divides the polynomial kx^3 - 2x^2 + 25x - 26 without remainder, then find the value of k


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Answer 1

Answer:

3 is the answer.

Step-by-step explanation:

$k {x}^{3} - 2 {x}^{2} + 25x - 26$

$(x - 1 )= 0 \\ = > x = 1$

$= > Put \: the \: value \: of \: x \: as \: 1.$

$= > k( {1}^{3} ) - 2( {1}^{2} ) + 25 \times( 1) - 26 = 0$

$= > k - 2 + 25 - 26 = 0$

$= > k + 23 - 26 = 0$

$= > k - 3 = 0$

$= > k = 3$

Therefore,the answer is 3.