Question

If (x+1) factor of the polynomial ax^2+bx+c. Then prove b=a+c.

Answer 1

Answer:

$Suppose \: F(x)= \: a {x}^{2} + bx + c \\ (x + 1) \: will \: be \: the \: factor \: of \: f(x) \: if \: f( - 1)=0 \\ so \: f( - 1) = 0 \\ a {( - 1)}^{2} + b( - 1) + c = 0 \\ > a - b + c = 0 \\ > a + c = b \\ > b = a + c$

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