Math, asked by monalisachakrab6513, 10 months ago

If x=1 is 0 of a polynomial f(x)=x3-2x2+4x+k

Answers

Answered by decentdileep
2

f(x)=x3-2x2+4x+k

x+1=0

x=-1

f(-1)=(-1)^3-2(-1)^2+4(-1)+k

f(-1)=-1-2(1)+4(-1)+k

f(-1)=1-2-4+k

f(-1)=-5+k=0

f(-1)=k=5

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