if (x+1) is a common factor of the polynomial x2+px q and x2+mx+n then find the value of x
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Step-by-step explanation:
(x + a) is a factor of x2 + px + q
(-a)2 + p(-a) + q = 0
a2 - ap + q = 0 ...(i)
(x + a) is a factor of x2 + mx + n
(-a)2 + m (-a) + n = 0
a2 - am + n = 0 ...(ii)
From (i) and (ii),
-ap + am + q - n = 0
a(m - p) = n - q
a =
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