Question

if x=1 is a common root of the equation ax^2+ax+3=0 and x^2+x+b=0 then ab = ​

Answer 1

Answer:

We have to prove that

ax² +ax +3=0------- (i)

x+x+b=0----------(ii)

we have to find the value of a and b then their product will give the answer i.e

ab=3

Now Given

x=1.

For equation (i)

ax²+ax+3=

=> a(1)² + a(1) +3=0 [putting the value of x]

=> a+a=-3

=> 2a= -3

=>a = -1.5

Now Putting the value of X in equation (ii) we get

1+1+b=0

=>2+b=0

=> b= -2

Now according to the given problem

ab= -1.5 * - 2

=> ab= 3 [Proved]

Answer 2

Answer:

Now We have to prove that

ax² +ax +3=0------- (i)

x+x+b=0----------(ii)

we have to find the value of a and b then their product will give the answer i.e

ab=3

Now Given

x=1.

For equation (i)

ax²+ax+3=

=> a(1)² + a(1) +3=0 [putting the value of x]

=> a+a=-3

=> 2a= -3

=>a = -1.5

Now Putting the value of X in equation (ii) we get

1+1+b=0

=>2+b=0

=> b= -2

Now according to the given problem

ab= -1.5 * - 2

=> ab= 3 [Proved]

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