If x=1 is a common root of the equation ax2 + ax + 3 = 0 & X2 + x + b = 0 , then the value of ab is
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3
Answer:
3
Step-by-step explanation:
if x=1
therefore,
ax²+ax+3=0
a(1)²+a(1)+3=0
a+a+3=0
2a+3=0
- a=-3/2
also,
x²+x+b=0
(1)²+1+b=0
1+1+b=0
2+b=0
- b=-2
so,
ab=-3/2*-2
=-3*-1
=3
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