Question

if (x-1)is a factor kx power 2-root2x+1 find the value of k​

Answer 1

Answer:

k = √2 - 1

Step-by-step explanation:

Given,

$p(x) = {kx}^{2} - \sqrt{2}x + 1$

Whose one of the factor is (x - 1)

Then zeros of the polynomial would be 1

So,

$p(1) = k(1 {)}^{2} - \sqrt{2} (1) + 1$

$= > k - \sqrt{2} + 1 = 0$

$= > k = \sqrt{2} - 1$

The value of k is √2 - 1