Question

If (x+1) is a factor of 2x^2 +ax^2+ 2bx+1, then find the values of a and b given that 2a-3b=4.

Answer 1

Answer:

Step-by-step explanation:

Given polynomial

f(x)=2x^2 +ax^2+ 2bx+1

X+1 is the factor so,

X=-1

Substitute the value of x

2 × (-1)² +a ×(-1)² + 2×(-1)× b+1=f(-1)

2+a-2b+1=0 -------->[since x+1 is the factor ]

a-2b=-3 ------>Eq1

2a-3b=4 ------->Eq2

Solve both the eq by either substituting method or elimination and get the value of a and b