If x+1 is a factor of 2x^3 + 3x^2 + 2bx + 1 and 2ab - 3b= 4 then find the value of a and b
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x+1=0. (given)
x= -1
=2x^3+3x^2+2bx+1
=2(-1)^3+3(-1)^2+2b(-1)+1
=2(-1)+3(1)-2b+1
=-2+3-2b+1
=1-2b+1
=2-2b
-2=-2b
2=2b
2/2=b
Therefore, b=1
2ab-3b=4
2a(1)-3(1)-4=0
2a-3-4=0
2a-7=0
2a=7
a=7/2
x= -1
=2x^3+3x^2+2bx+1
=2(-1)^3+3(-1)^2+2b(-1)+1
=2(-1)+3(1)-2b+1
=-2+3-2b+1
=1-2b+1
=2-2b
-2=-2b
2=2b
2/2=b
Therefore, b=1
2ab-3b=4
2a(1)-3(1)-4=0
2a-3-4=0
2a-7=0
2a=7
a=7/2
vaishushrikhande21:
I hope I helped you
Yes, thank you
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