Math, asked by ayushseth1259, 10 months ago

If (X+1) is a factor of 2x^3+4x+6 find remaining factors *
2 points
(X+3)(x-2)
(2x^2-2x+6)
(x-3)(X+3)
(x-3)(X+1)

Answers

Answered by dhanushgowda63008
1

Answer:

16-Jul-2019 · ... (i) (x+1)^2 = 2(x – 3) (x+1)^2 = 2(x – 3) x2+12+2×x×1=2(x−3) x2 + 1 + 2x = 2x – 6 x2 + 1+ 2x – 2x + 6 ...

Step-by-step explanation:

16-Jul-2019 · ... (i) (x+1)^2 = 2(x – 3) (x+1)^2 = 2(x – 3) x2+12+2×x×1=2(x−3) x2 + 1 + 2x = 2x – 6 x2 + 1+ 2x – 2x + 6 ...

Answered by sunilyadav222109
0

(x+3) (x-2)

(2x^2-2x+6)

(x-3) (x+3)

( x-3)( x -1)

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