If x+1 is a factor of 2x^3+ax^2+2bx+1 and 2a-3b=4, then find the value of a and b.
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Solution :
°.° x + 1 is a factor of p ( x ) = 2x^3 + ax^2 + 2bx + 1
Then, by using the factor theorem,
p ( -1 ) = 0
=> -2 + a - 2b + 1 = 0
=> a - 2b = 1 -------------- (equation 1)
Also,
2a - 3b = 4 -------------- (equation 2)
On multiplying equation (1) by 2 and equation (2) by 1, we get
2a - 4b = 2
2a - 3b = 4
- + = -
- b = - 2
.°. b = 2
On putting b = 2 in equation (1), we get
a - 2 × 2 = 1
=> a - 4 = 1
=> a = 1 + 4
=> a = 5
.°. a = 5
Thus,
.°. a = 5 and b = 2.
Answer : a = 5 and b = 2
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