Question

If x-1 is a factor of 2x^3 + x^2 - 4x + m, then find the value of m

Answer 1

Given equation

$2x^{3}+x^{2} -4x+m=0$

x-1 is a zero of the polynomial

$\implies x-1=0\\\implies x = 1$

Substituting, x = 1 in the equation, we get,

$\implies 2(1)^{3} + (1)^{2} - 4(1) + m = 0\\\implies 2+1-4+m=0\\\implies 3-4+m=0\\\implies -1+m=0\\\implies m =1$

$\boxed{\boxed{\bold{Therefore, \ the \ value \ of \ m \ is \ 1}}}}}}}}$

                                                           

Answer 2

Answer:

m=1

Step-by-step explanation:

x-1=0

x=1

p(x)=2x^3+x^2-4x+m

p(1)=2(1)^3+(1)^2-4(1)+m

=2+1-4+m

therefore,

2+1-4+m=0

3-4+m=0

-1+m=0

m=1

.

.

.

.

.

MARK ME AS BRAINLIEST