if x+1 is a factor of 2x cube + ax square + 2bx +1 then find the values of a and b given that 2a-3b = 4
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Answer:
a = 5
b= 2
Step-by-step explanation:
given that x+1 is a factor
then x+1 = 0
x= -1
the equation is 2x^3 + ax^2 + 2bx +1
substitute x = - 1 in the above equation
2 ( -1 )^3 + a ( -1 )^2 + 2b( - 1 ) +1 = 0
-2 + a - 2b +1=0
-1 + a - 2b = 0
a - 2b = 1
multiply by 2
2 ( a - 2b ) = 2 (1 )
2a - 4b = 2 ..............consider as equation 1
given that 2a - 3b = 4 ..........consider as equation 2
do equation 1 - 2
2a-4b=2
( - ) 2a-3b=4
we will get
-b = -2
b = 2
now substitue b value in anyone of the equation 1 or equation 2
i am substituting in equation 2
2a - 3(2) = 4
2a- 6 = 4
2a = 6+4
2a = 10
a = 10/2
a = 5
pls mark as brainliest answer
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