If x+1 is a factor of 2x3 +ax2+2bx +1,then find the values of a and b given that 2a-3b=4
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x-a=x+1
a= -1
f(x)=f(a)= 2(-1)³ +a-2b+1
0 =a-2b-1
a-2b=1 ....eqn1
2a-3b=4....eqn2
multiplying eqn1 by 2 and subtracting eqn1 and eqn2 we get,
2a-4b=2
2a-3b=4
(-) (+) (-)
b=2
putting the value of b in eqn2 we get,
2a-3*2=4
2a=10
a=10/2 =5
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