Question

If(x-1)is a factor of 2xsquare-2a find the value of a fast

Answer 1

Answer:

x-1=0

x=1

now

2x²-2a=0

2-2a=0

a=1

Step-by-step explanation:

Answer 2

Step-by-step explanation:

First Look at the attachment

As x-1 is a factor of x^2-2a

Then on dividing x^2-2a with x-1 the remainder should be 0

So, -2a+2=0

=> 2a=2

=> a=1

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