Question

If x-1 is a factor of a^2×x^3 - 3×a×x + 3×a -1 ,find the value of a.​

Answer 1

Answer:

a = ±1

Step-by-step explanation:

x - 1 is a factor

x - 1 = 0

x = 1

a²x³ - 3ax + 3a - 1 = 0

Substituting the value of x

0 = a²(1)³ - 3a(1) + 3a - 1

0 = a² - 3a + 3a - 1

a² - 1 = 0

a² = 1

a = ±1

Hope this helps! :)

Answer 2

Answer:

x-1 is the solution of equation a²x³ - 3ax + 3a -1

it means solution of the p(x) is:

x-1 = 0

x = 1

putting the value of x in given equation gives us

a²(1)³ - 3a(1) + 3a -1

= a² - 3a + 3a -1

= a² - 1

using the identity a²-b²= (a+b)(a-b)

= (a+1)(a-1)

so, a = 1, -1.

hope it helps. kindly mark it brainliest,