Question

if x-1 is a factor of ax^2-root2+1 the value of a is

Answer 1

Answer:

if x-1 is a factor then x-1=0 so x=1 subs 1 in equation

so ax^2 - root 2 +1 =0

so a *1^2= root 2 +1

so a = root 2 +1

hope it helped pls brainliest

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

x - 1 is factor

So x - 1=0

x=1

ax^2-√2x+1=0

a(1)^2-√2(1)+1=0

a-√2+1=0

a=√2-1

This is the answer

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