Question

if x+1 is a factor of ax^3 +x^2-2x+4a-6,find a

Answer 1

$05 {211 + 1 = \div 5 < 1}^{2}$

Answer 2

Hey there, here is your solution

Factor = X + 1

then, by remainder theorem,

X + 1 = 0

X = -1

p( -1 ) = a (-1)^3 + (-1)^2 - 2 (-1) + 4a - 6

0 = -1a + 1 + 2 + 4a - 6

0 = -1a - 3 + 4a

3 = 3a

a = 1Ans .