Question

if (x+1) is a factor of ax^3 +x^2-2x+4x-9 find the value of a ​

Answer 1

Answer:

a=2

Step-by-step explanation:

Let p(x)=ax³+x²−2x+4a−9

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]⇒a(−1)³+(−1)²−2(−1)+4a−9=0

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]⇒a(−1)³+(−1)²−2(−1)+4a−9=0⇒a(−1)+1+2+4a−9=0

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]⇒a(−1)³+(−1)²−2(−1)+4a−9=0⇒a(−1)+1+2+4a−9=0⇒−a+4a−6=0

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]⇒a(−1)³+(−1)²−2(−1)+4a−9=0⇒a(−1)+1+2+4a−9=0⇒−a+4a−6=0⇒3a−6=0

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]⇒a(−1)³+(−1)²−2(−1)+4a−9=0⇒a(−1)+1+2+4a−9=0⇒−a+4a−6=0⇒3a−6=0⇒3a=6

Let p(x)=ax³+x²−2x+4a−9As (x+1) is a factor of p(x)∴p(−1)=0 [By factor theorem]⇒a(−1)³+(−1)²−2(−1)+4a−9=0⇒a(−1)+1+2+4a−9=0⇒−a+4a−6=0⇒3a−6=0⇒3a=6⇒a=2

Answer 2

Answer:

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Step-by-step explanation:

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