Math, asked by SimranPatnaik6692, 4 months ago

if ( x +1 ) is a factor of ax cube + 2x square -x + 3a -7 then find the value of A

Answers

Answered by aditya04112005
0

Answer:

value of a will be 2

please mark it the brainiest

Answered by Aryan0123
5

GIVEN :-

(x + 1) is a factor of ax³ + 2x² - x + 3a - 7

TO FIND :-

Value of a = ?

SOLUTION :-

By using factor theorem,

(x + 1) = 0

➝ x = 0 - 1

x = -1

p(x) = ax³ + 2x² - x + 3a - 7 = 0

Now, substitute the value of x in the given equation.

p(-1) = a(-1)³ + 2(-1)² - (-1) + 3a - 7 =  0

p(-1) = -1a + 2 + 1 + 3a - 7 = 0

p(-1) = -1a + 3 + 3a - 7 = 0

p(-1) = -1a + 3a - 4 = 0

p(-1) = 2a - 4 = 0

p(-1) = 2a = 4

p(-1) = a = 2

So, the value of a = 2

Know more:

  • Factor theorem states that a polynomial f(x) has a factor (x - a) if and only if f(a) = 0
  • Remainder theorem states that when a polynomial p(x) is divided by any binomial (x - a), then the remainder so obtained is p(a)
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