if ( x +1 ) is a factor of ax cube + 2x square -x + 3a -7 then find the value of A
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value of a will be 2
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GIVEN :-
(x + 1) is a factor of ax³ + 2x² - x + 3a - 7
TO FIND :-
Value of a = ?
SOLUTION :-
By using factor theorem,
(x + 1) = 0
➝ x = 0 - 1
➝ x = -1
p(x) = ax³ + 2x² - x + 3a - 7 = 0
Now, substitute the value of x in the given equation.
p(-1) = a(-1)³ + 2(-1)² - (-1) + 3a - 7 = 0
➥ p(-1) = -1a + 2 + 1 + 3a - 7 = 0
➟ p(-1) = -1a + 3 + 3a - 7 = 0
↦ p(-1) = -1a + 3a - 4 = 0
⇢ p(-1) = 2a - 4 = 0
➳ p(-1) = 2a = 4
⇒ p(-1) = a = 2
So, the value of a = 2
Know more:
- Factor theorem states that a polynomial f(x) has a factor (x - a) if and only if f(a) = 0
- Remainder theorem states that when a polynomial p(x) is divided by any binomial (x - a), then the remainder so obtained is p(a)
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