Math, asked by ayush95598, 10 months ago

if X + 1 is a factor of ax cube + x square - 2 X + 4 x minus 4 a minus 9 find the value of a​

Answers

Answered by pc0354525
4

Answer:

The answer is 2 .

Step-by-step explanation:

Let, f(x) = ax³ + x² - 2x + 4a - 9

Given (x + 1) is a factor of  f(x), so f(-1) = 0

f(x) = ax³ + x² - 2x + 4a - 9

f(- 1) = a( - 1 )³ + (- 1 )² - 2  (- 1) + 4a - 9

0 = - 1a + 1 + 2 + 4a - 9

0 = - 1a + 4a + 1 + 2 - 9

0 = 3a + 3 - 9

0 = 3a - 6

-3a = - 6

a = 6/3

a = 2

Hence, the value of a is 2 .

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