if X + 1 is a factor of ax cube + x square - 2 X + 4 x minus 4 a minus 9 find the value of a
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Answer:
The answer is 2 .
Step-by-step explanation:
Let, f(x) = ax³ + x² - 2x + 4a - 9
Given (x + 1) is a factor of f(x), so f(-1) = 0
f(x) = ax³ + x² - 2x + 4a - 9
f(- 1) = a( - 1 )³ + (- 1 )² - 2 (- 1) + 4a - 9
0 = - 1a + 1 + 2 + 4a - 9
0 = - 1a + 4a + 1 + 2 - 9
0 = 3a + 3 - 9
0 = 3a - 6
-3a = - 6
a = 6/3
a = 2
Hence, the value of a is 2 .
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